WAEC Past Questions

WAEC Physics 2024
Questions & Answers

20 questions · Correct answers highlighted · 20 with explanations

Explanations reviewed August 2026

This WAEC Physics 2024 assessment measures student understanding across a wide spectrum of topics including mechanics, thermodynamics, electrostatics, optics, and modern physics. Several questions consistently highlight themes such as mirror and lens reflection/refraction, momentum and forces in motion, and capacitance alongside electrostatic forces. For effective preparation, ensure you thoroughly read the accompanying explanations for every item to reinforce your conceptual foundation rather than just memorizing answer keys.

20 Total Questions
2024 Exam Year
20 With Explanations

Topics in this paper

Mechanics and Motion (10) Electricity and Circuits (8) Geometrical Optics (7) Thermal Physics (3) Properties of Matter (3) Modern Physics (3) Electrostatics (3) Nuclear Physics (2) Simple Harmonic Motion (1)
Ready to test yourself? Take the full WAEC Physics 2024 CBT quiz — timed, just like the real exam.
Start Quiz
1
Question 1 of 20
WAEC · Physics · 2024

The vacuum space and silvered surfaces of a vacuum flask walls are to respectively

A. minimize conduction and convection and prevent radiation
B. prevent conduction and convection and minimize radiation
C. prevent conduction and minimize convection and radiation
D. minimize conduction and convection and minimize radiation
Explanation

Students might mistakenly choose option A or C by reversing the specific roles played by the different parts of the container. The vacuum space acts as an absolute barrier that eliminates the medium required for conduction and convection, completely halting those two transfer methods. Meanwhile, the silvered inner and outer surfaces tackle thermal radiation by reflecting radiant heat back into the flask. Common mistake: Mixing up which structural feature prevents conduction/convection versus which addresses radiation.

2
Question 2 of 20
WAEC · Physics · 2024

The magnitude of the acceleration of a moving object is equal to the

A. gradient of a displacement-time graph
B. gradient of a velocity-time graph
C. area below a force-time graph
D. area below a velocity-time graph
Explanation

Students might mistakenly select option A by confusing velocity-time graphs with displacement-time graphs, where the gradient represents velocity rather than acceleration. Acceleration is formally defined as the rate of change of velocity over time, which corresponds geometrically to the gradient or slope of a velocity-time graph. Common mistake: Confusing the slope of a displacement-time graph (velocity) with the slope of a velocity-time graph (acceleration).

3
Question 3 of 20
WAEC · Physics · 2024

In which of the following states is maximum pressure exerted on a person?

A. Standing on two feet
B. Standing on one foot
C. Lying on the floor
D. Kneeling on the floor
Explanation

Students might choose option A, C, or D by underestimating the effect that surface area has on pressure distribution. Since pressure is calculated as force divided by area, and the downward force exerted by body weight remains constant across all options, standing on a single foot halves the contact surface area, thereby maximizing the resulting pressure. Common mistake: Forgetting that reducing the contact area while keeping weight constant significantly increases pressure.

4
Question 4 of 20
WAEC · Physics · 2024

What are cathode rays?

A. Stream of electrons
B. Beam of neutrons
C. Beam of protons
D. Stream of alpha particles
Explanation

Students might mistakenly select option B, C, or D by confusing cathode rays with subatomic particles derived from nuclear reactions or channel rays. Cathode rays are specifically generated inside a vacuum tube under high voltage and consist of a high-speed stream of electrons emitted from the cathode. Common mistake: Confusing cathode rays (electrons) with anode rays or protons.

5
Question 5 of 20
WAEC · Physics · 2024

The capacitance of a parallel plate capacitor

A. decreases when the separation between the plates decreases
B. increases when the potential difference between the plates is increased
C. is greater without a dielectric between the plates than with dielectric
D. is greater with dielectric between the plates than without dielectric
Explanation

Students might mistakenly pick option C by assuming that inserting an insulating material somehow hinders charge storage. Capacitance is directly enhanced when a dielectric material is placed between the conducting plates because it increases the capacitance value by a factor greater than one, following the relationship C = epsilon naught A over d scaled by the dielectric constant. Common mistake: Believing that adding a dielectric material decreases or has no effect on a capacitor's storage capacity.

6
Question 6 of 20
WAEC · Physics · 2024

A ray of light travels from a less dense medium to a denser medium. How are the speed and frequency of the light affected? The speed

A. increases and the frequency increases
B. decreases and the frequency decreases
C. increases and the frequency remains the same
D. decreases and the frequency remains the same
Explanation

Students might mistakenly select option A or B by assuming that wave frequency changes when light transitions between optical mediums. When a light ray enters a denser medium from a less dense medium, its speed decreases because the refractive index increases (v = c/n). However, the frequency remains entirely unaltered because frequency is an intrinsic characteristic determined solely by the wave source. Common mistake: Assuming that changes in light speed through a medium also cause a shift in its frequency.

7
Question 7 of 20
WAEC · Physics · 2024

The function of a fuse in an electric circuit is to

A. break the circuit when the current exceeds a certain value
B. save energy by reducing the voltage
C. ensure that the current exceeds a certain value
D. save energy by reducing the current
Explanation

Students might choose option B or D by confusing circuit safety devices with voltage regulators or power-saving appliances. A fuse is specifically designed as a thin sacrificial wire that melts and interrupts the electrical path whenever current surges past a designated threshold, protecting the wider circuit from overloads. Common mistake: Assuming a fuse regulates or reduces normal operating current to save energy.

8
Question 8 of 20
WAEC · Physics · 2024

A body moves with uniform velocity when the resultant force on it is

A. greater than the frictional force acting on it
B. less than the frictional force acting on it
C. equal to zero
D. equal to unity
Explanation

Students might mistakenly select option A or B by assuming that movement requires an unbalanced forward or backward force. According to Newton's first law of motion, a body maintains a constant, uniform velocity whenever the net resultant force acting upon it equals zero, meaning opposing forces like friction are perfectly balanced. Common mistake: Believing that a net forward force is required to keep an object moving at a steady velocity.

9
Question 9 of 20
WAEC · Physics · 2024

The law of conservation of momentum is stated for closed and isolated system. What are the two conditions for a system to be closed and isolated?

A. No external force acts on the system and there is no change in mass of the system
B. No external force acts on the system and there is a gain in mass
C. No external force acts on the system and there is a loss in mass
D. An external force acts on the system and there is no change in mass
Explanation

Students might mistakenly select option B, C, or D by assuming that mass fluctuations or external forces do not disrupt momentum conservation. For the law of conservation of momentum to hold true, the system must be completely isolated so that no external forces act upon it, and it must be closed so that no mass enters or leaves the system. Common mistake: Overlooking the requirement that system mass must remain constant alongside zero external forces.

10
Question 10 of 20
WAEC · Physics · 2024

A stone of mass 200g attached to a string is made to revolve in a vertical circle of radius 1.5m at a steady speed of 5ms⁻¹. Calculate the tension in the string at the bottom of the circle. [g = 10ms⁻²]

A. 5.3N
B. 3.3N
C. 2.0N
D. 1.3N
Explanation

Students might mistakenly choose option B by calculating the centrifugal force component alone and forgetting to add the weight vector. At the bottom of a vertical circular path, the string must support both the downward weight of the stone (mg) and provide the upward centripetal force (mv squared over r). Substituting the mass of 0.2kg, speed of 5ms⁻¹, radius of 1.5m, and gravity of 10ms⁻² gives 3.33N for the centripetal component and 2.0N for the weight, resulting in a total tension of 5.33N. Common mistake: Omitting the weight of the object when calculating tension at the lowest point of a vertical loop.

11
Question 11 of 20
WAEC · Physics · 2024

To convert a milli-ammeter to an ammeter, it is necessary to connect a resistor of

A. low value in series with it
B. high value in series with it
C. low value in parallel with it
D. high value in parallel with it
Explanation

Students might mistakenly choose option A or B by confusing ammeter conversion with voltmeter modifications. To convert a milli-ammeter into an ammeter capable of handling higher currents, a low-value shunt resistor must be connected in parallel with the device to divert excess current safely away from the sensitive meter movement. Common mistake: Placing the shunt resistor in series instead of parallel when converting a meter range.

12
Question 12 of 20
WAEC · Physics · 2024

An object is placed 1.5m from a plane mirror. How far is the image from the object?

A. 3.0m
B. 1.5m
C. 1.0m
D. 0.3m
Explanation

Students might mistakenly select option B by reading only the distance from the object to the mirror rather than calculating the total span requested. In a plane mirror, the virtual image forms directly behind the glass at a distance equal to the object distance (1.5m), meaning the total separation distance between the object and its image is 1.5m plus 1.5m, totaling 3.0m. Common mistake: Reporting the distance from the mirror to the image instead of the total distance between the object and the image.

13
Question 13 of 20
WAEC · Physics · 2024

Chromatic aberration in lenses can be corrected by using a combination of

A. diverging and converging lenses
B. an opaque material to cover the rims of lenses
C. wide parallel beams on the lens’s surface
D. a thin convex lens
Explanation

Students might mistakenly select option B or D by choosing aperture stops or single lens adjustments that fail to address dispersion across wavelengths. Chromatic aberration occurs because different colors refract at varying focal lengths, which is successfully corrected by pairing a converging crown glass lens with a diverging flint glass lens in an achromatic doublet. Common mistake: Trying to fix chromatic dispersion using single lenses or rim covers instead of a combined lens system.

14
Question 14 of 20
WAEC · Physics · 2024

A cube of wood of side 10.0cm floats vertically in water with 4.5cm of its length submerged. Calculate the density of the wood. [Density of water = 1gcm⁻³]

A. 0.450gcm⁻³
B. 0.203gcm⁻³
C. 0.090gcm⁻³
D. 0.045gcm⁻³
Explanation

Students might select option B or C by miscalculating the ratio of submerged length to total height. The density of the floating wood relative to water equals the fraction of its submerged volume to total volume, which is calculated as 4.5cm submerged divided by the 10.0cm total side length, yielding 0.45gcm⁻³ when multiplied by the water density of 1gcm⁻³. Common mistake: Multiplying or dividing incorrect dimension ratios when applying the floatation density formula.

15
Question 15 of 20
WAEC · Physics · 2024

A temperature of 60°C is equivalent to

A. 25°F
B. 50°F
C. 140°F
D. 108°F
Explanation

A student might incorrectly choose options like 108°F by forgetting to add the 32 offset after scaling. To determine the correct temperature, multiply the Celsius value 60 by 9/5 (or 1.8) to get 108, then add 32 to arrive at 140°F. Common mistake: forgetting to include the final addition of 32 in the conversion formula.

16
Question 16 of 20
WAEC · Physics · 2024

All of the following uses are practical application of x-ray except

A. the treatment of tumours
B. determining the depth of a mine
C. dental operation
D. detecting fracture in bones
Explanation

Options such as dental operation or detecting fracture in bones might look plausible because x-rays are famously utilized in medical imaging and therapy. However, finding the depth of a mine relies instead on seismic surveys. Common mistake: confusing medical and geological survey techniques.

17
Question 17 of 20
WAEC · Physics · 2024

Two isolated charged spheres each of magnitude +1.0 × 10⁻⁶C are separated by a distance of 2.0 × 10⁻¹m. Calculate the magnitude of the electrostatic force between them. [K = 1/(4πε₀) = 9 × 10⁹Nm²c⁻²]

A. 2.25 × 10⁻¹N
B. 4.50 × 10⁻¹N
C. 2.25 × 10¹N
D. 4.50 × 10¹N
Explanation

A student might mistakenly select 2.25 × 10¹N or other values by miscalculating exponents during division. By applying Coulomb's law where force equals k times the square of the charge divided by the square of the distance, substituting 9 × 10⁹ for k, 1.0 × 10⁻⁶C for the charges, and 2.0 × 10⁻¹m for the separation gives 9 × 10⁻³ divided by 0.04, yielding 2.25 × 10⁻¹N. Common mistake: mishandling decimal placement when squaring the distance.

18
Question 18 of 20
WAEC · Physics · 2024

A particle of mass 3.6 × 10⁻⁶kg revolving around the earth has a radial acceleration of 4.3 × 10⁷ms⁻². Calculate the centripetal force of the particle.

A. 6.25 × 10⁻¹⁴N
B. 1.55 × 10⁻²N
C. 1.55 × 10²N
D. 2.00 × 10⁻²N
Explanation

One might mistakenly pick 6.25 × 10⁻¹⁴N by mistakenly dividing instead of multiplying the given values. Centripetal force is calculated as mass multiplied by radial acceleration, so taking 3.6 × 10⁻⁶kg and multiplying by 4.3 × 10⁷ms⁻² results in 1.548 × 10²N, which rounds to 1.55 × 10²N. Common mistake: performing division of mass and acceleration instead of multiplication.

19
Question 19 of 20
WAEC · Physics · 2024

For a convex lens to form a real image, the distance between the object and the screen will

A. equal to the focal length of the lens
B. less than the focal length of the lens
C. twice the focal length of the lens
D. four times the focal length of the lens
Explanation

Distractors like twice the focal length might seem correct because a real image can be formed at 2f, but that describes the object position rather than the total object-screen separation. A convex lens forms a real image with a minimum object-to-screen distance of 4f, which occurs precisely when the object is placed at 2f and its image is formed at 2f. Common mistake: confusing the object-to-lens distance with the total object-to-screen distance.

20
Question 20 of 20
WAEC · Physics · 2024

Light of energy 1.1 × 10⁻¹⁸J is incident on a metal with a threshold energy of 6.6 × 10⁻¹⁹J. Calculate the maximum energy of the ejected electrons.

A. 1.0 × 10⁻¹⁸J
B. 4.5 × 10⁻¹⁹J
C. 2.2 × 10⁻¹⁹J
D. 1.2 × 10⁻¹⁸J
Explanation

Options such as 1.0 × 10⁻¹⁸J might tempt a student who accidentally subtracts incorrectly or misinterprets the exponents. Maximum kinetic energy of the ejected electrons is found by subtracting the threshold energy 6.6 × 10⁻¹⁹J from the incident energy 1.1 × 10⁻¹⁸J (expressed as 11 × 10⁻¹⁹J), giving 4.4 × 10⁻¹⁹J, which approximates to 4.5 × 10⁻¹⁹J. Common mistake: failing to align the powers of ten before performing subtraction.

Now practice in exam mode

You've studied the answers — now test yourself under real exam conditions with the timer running.

Start WAEC Physics 2024 Quiz
Back to 2024 Start Page
Offline App

Study WAEC Physics offline — no data needed

Get the WAEC app for Physics and every other subject — practice anywhere, even with no internet connection.

Download the App Free to install · One-time unlock for full access