JAMB Past Questions

JAMB Biology 2018
Questions & Answers

40 questions · Correct answers highlighted · 40 with explanations

40 Total Questions
2018 Exam Year
40 With Explanations
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1
Question 1 of 40
JAMB · Biology · 2018

A group of closely related organisms capable of interbreeding to produce fertile offspring are known as members of a

A. kingdom
B. class
C. family
D. species
Explanation

Options A, B, or C might catch a student's eye if they confuse broad taxonomic tiers with the specific rank defined by reproductive capability. Evaluating the biological definition provided leads us to focus on the unique ability to produce fertile offspring. Consequently, option D is correct because a species is a group of organisms that can interbreed to produce fertile offspring. Common mistake: Selecting broader categories like kingdom or family which contain diverse organisms unable to interbreed successfully.

2
Question 2 of 40
JAMB · Biology · 2018

A beaker of pond water containing few specimens of Euglena was placed in a dark room for two weeks. At the end of this period, the specimens of Euglena were still alive because they were able to carry out holistic nutrition

A. using sunlight
B. using photosynthesis
C. better adapted to life in darkness than to life in light
D. not overcrowded
Explanation

One might choose option A, B, or D by incorrectly assuming the organisms perished without light or focusing on population density rather than metabolic capability. When considering dark environments where sunlight is absent, survival depends on an alternative way to obtain nourishment. Hence, option C is correct because Euglena can switch to heterotrophic nutrition in darkness, absorbing nutrients, making them better adapted to dark conditions. Common mistake: Assuming all photosynthetic organisms automatically die in the dark without considering alternative nutritional adaptations.

3
Question 3 of 40
JAMB · Biology · 2018

The cytoplasm of the cell is considered a very important component because it

A. regulates the amount of energy in the cell
B. suspends all cell organelles
C. is the outermost part of the cell
D. is solely responsible for cell division
Explanation

A student might mistakenly select option A, C, or D by attributing cellular boundaries, energy regulation, or division entirely to the fluid interior. Analyzing the structural layout of a typical cell shows that the fluid matrix functions primarily to hold internal elements in place while facilitating metabolic flow. Thus, option B is correct because the cytoplasm suspends organelles, providing a medium for cellular processes. Common mistake: Confusing the role of the cytoplasm with the nucleus or cell membrane functions.

4
Question 4 of 40
JAMB · Biology · 2018

Which of the following processes is responsible for the movement of water into a plant cell?

A. diffusion
B. osmosis
C. active transport
D. transpiration
Explanation

Options A, C, or D might be selected if a student lumps all transport mechanisms together without considering the specific substance moving across membranes. Because the question specifies the movement of water specifically, we must look at the specialized transport across a semi-permeable boundary driven by concentration gradients. Therefore, option B is correct since osmosis moves water into a plant cell through a semi-permeable membrane from higher to lower water concentration. Common mistake: Confusing general solute diffusion with the specific movement of water known as osmosis.

5
Question 5 of 40
JAMB · Biology · 2018

Which of the following is an example of a simple diffusion process in living organisms?

A. movement of glucose into cells
B. movement of oxygen into cells
C. absorption of water by roots
D. transport of sodium ions
Explanation

A student might choose options A, C, or D by selecting active or specialized transport types that require carrier proteins or do not occur via simple concentration gradients. Reviewing how small molecules traverse cell membranes without requiring external energy reveals a passive process driven by gradients. This makes option B correct because oxygen moves into cells by simple diffusion down its concentration gradient without energy input. Common mistake: Mistaking facilitated transport or root water absorption for simple unassisted diffusion.

6
Question 6 of 40
JAMB · Biology · 2018

In a plant cell, the role of the membrane is played by the

A. nucleolus
B. cell wall
C. cytoplasm
D. mitochondrion
Explanation

One might mistakenly choose option A, C, or D by focusing on internal cell components rather than the rigid outer boundary of plant cells. When looking at what defines and protects a plant cell from the outside environment, we look to the rigid outer layer that provides structural integrity. Hence, option B is correct because the cell wall in plant cells provides structural support, analogous to a membrane’s role in other contexts. Common mistake: Confusing the internal cytoplasm or nucleolus with the structural boundary provided by the cell wall.

7
Question 7 of 40
JAMB · Biology · 2018

Red blood cells were found to have burst open after being placed in distilled water for an hour. This phenomenon is known as

A. plasmolysis
B. diffusion
C. haemolysis
D. wilting
Explanation

Options A, B, or D might be selected if a student confuses the bursting of animal cells with plant cell shrinking or general particle movement. Since distilled water creates a hypotonic environment causing water to rush into red blood cells until they rupture, we identify a specific hemolytic event. Thus, option C is correct because haemolysis occurs when red blood cells burst in hypotonic distilled water due to water influx. Common mistake: Confusing haemolysis with plasmolysis, which is the shrinking of plant cells in hypertonic solutions.

8
Question 8 of 40
JAMB · Biology · 2018

The curvature movement of plants in response to the stimulus of water is called

A. hydrotropism
B. geotropism
C. phototropism
D. thigmotropism
Explanation

A student could choose option B, C, or D by mixing up different tropic responses such as gravity, light, or touch stimuli. Focusing specifically on the water stimulus mentioned in the scenario points us directly to a moisture-seeking directional growth. Therefore, option A is correct since hydrotropism is the plant growth response toward water, such as roots seeking moisture. Common mistake: Confusing hydrotropism with geotropism or phototropism, which respond to gravity and light respectively.

9
Question 9 of 40
JAMB · Biology · 2018

The overall reaction in glycolysis can be summarised as

A. C6H12O6 → 3C3H4O3 + 4H
B. C6H12O6 → 2C3H4O3 + 4H + 2ATP
C. C6H12O6 → 2C3H4O3 + 4H + 2ATP
D. C6H12O6 → 2C3H4O3 + 4H + 2ADP
Explanation

Options A, C, or D might be chosen due to minor numerical or chemical symbol mismatches in the reaction balance. By breaking down the breakdown of one glucose molecule during cellular respiration steps, the pathway yields two pyruvate molecules along with specific energy and hydrogen carriers. Consequently, option B is correct because glycolysis converts glucose (C6H12O6) into two pyruvate molecules (C3H4O3), yielding 2 ATP and 4H (as NADH). Common mistake: Overlooking the correct yield of ATP and hydrogen atoms when balancing the glycolysis formula.

10
Question 10 of 40
JAMB · Biology · 2018

The longest bone in the body is the

A. humerus
B. femur
C. scapula
D. tibia
Explanation

A student might mistakenly select option A, C, or D by confusing upper body skeletal elements or lower leg bones with the primary upper leg structure. Examining human skeletal anatomy reveals that the upper leg houses the longest and heaviest skeletal element in the human framework. Thus, option B is correct because the femur, or thigh bone, is the longest bone in the human body, supporting the leg. Common mistake: Confusing the femur with the tibia or humerus.

11
Question 11 of 40
JAMB · Biology · 2018

Which of the following structures is not a skeletal material?

A. Chitin
B. Cartilage
C. Bone
D. Muscle
Explanation

One might select option A, B, or C if they confuse structural support tissues with contractile tissue elements. Since chitin, cartilage, and bone all serve rigid or semi-rigid structural functions in various organisms, we must find the option representing active contractile tissue. Therefore, option D is correct because muscle is a soft tissue, not a skeletal material, unlike chitin, cartilage, and bone, which provide structure. Common mistake: Mistaking muscle tissue for a skeletal component due to its prominent role in bodily movement.

12
Question 12 of 40
JAMB · Biology · 2018

The reason why the flow of blood through the capillaries is very slow is

A. to allow adequate time for exchange of materials
B. to increase blood pressure
C. to promote faster diffusion
D. to prevent backflow
Explanation

Options B, C, or D might seem plausible if a student associates blood movement speed with accelerating pressure or stopping backflow. Analyzing the microcirculatory system shows that narrow vessels require reduced velocity to ensure adequate functional transfers occur with surrounding tissue. This makes option A correct because slow blood flow in capillaries allows time for exchanging oxygen, nutrients, and waste with tissues. Common mistake: Assuming faster blood movement is always better, ignoring the time required for material exchange.

13
Question 13 of 40
JAMB · Biology · 2018

Which of the following groups of organisms has the kidney as their excretory organ?

A. Fishes, amphibians, birds, man
B. Fishes, amphibians, annelids, insects
C. Fishes, reptiles, birds, tapeworms
D. Fishes, protozoans, amphibians, man
Explanation

A student could mistakenly choose option B, C, or D by including invertebrates or simple organisms that utilize different structures like Malpighian tubules or flame cells for excretion. Reviewing vertebrate and advanced excretory systems shows a consistent reliance on renal organs across specific higher and aquatic animal groups. Hence, option A is correct because fishes, amphibians, birds, and humans have kidneys as excretory organs. Common mistake: Including organisms like insects or tapeworms which utilize entirely different excretory systems.

14
Question 14 of 40
JAMB · Biology · 2018

Which of the following features is not a characteristic of arteries?

A. possess valves at intervals throughout their length
B. have thick muscular and elastic walls
C. carry blood away from the heart
D. transport oxygenated blood with the exception of the pulmonary artery
Explanation

Options B, C, or D might be chosen if a student confuses structural traits unique to veins with those of the arterial network. Because arteries deal with high-pressure surges directly from the heart, they do not require the internal flaps used to stop blood pooling. Thus, option A is correct since arteries lack valves, which are found in veins to prevent backflow. Common mistake: Attributing venous valves to arteries, forgetting that only veins require valves against gravity.

15
Question 15 of 40
JAMB · Biology · 2018

Which of the statements below is valid?

A. The bird’s blood was always warmer than that of the lizard
B. The body temperature of the bird varied less than that of the lizard during changes in environmental conditions
C. The lizard was always warmer
D. The lizard’s blood temperature was constant
Explanation

A student might select option A, C, or D by making absolute assumptions about constant temperatures or universal reptile warmth. Recognizing the physiological difference between endothermic birds and ectothermic reptiles clarifies how their internal conditions react to environmental shifts. Therefore, option B is correct because birds, being warm-blooded, maintain a more stable body temperature than lizards, which are cold-blooded and vary with the environment. Common mistake: Assuming cold-blooded animals can maintain a constant internal temperature independent of outside weather.

16
Question 16 of 40
JAMB · Biology · 2018

The part of the ear which contains nerve cells sensitive to sound vibrations is the

A. cochlea
B. ampulla
C. tympanum
D. malleus
Explanation

Options B, C, or D might be mistakenly picked by confusing inner ear structures with middle ear bones or balance organs. Tracing the auditory pathway shows that the snail-shaped inner structure houses the specialized receptor cells responsible for translating mechanical movement into neural impulses. Consequently, option A is correct because the cochlea contains nerve cells that detect sound vibrations and transmit signals to the brain. Common mistake: Confusing the cochlea with the tympanum or ampulla when identifying auditory sensory structures.

17
Question 17 of 40
JAMB · Biology · 2018

Spectacles with convex lenses correct long-sightedness by

A. converging the light rays before they enter the eye
B. diverging the light rays before they enter the eye
C. reducing light intensity before it enters the eye
D. increasing light intensity before it enters the eye
Explanation

Students might mistakenly choose option B because they confuse the function of convex lenses with concave lenses, which diverge light for short-sightedness. Option A is correct because convex lenses bend incoming light rays inward, allowing them to converge and focus precisely on the retina for individuals with long-sightedness. Common mistake: Confusing whether convex lenses converge or diverge light rays.

18
Question 18 of 40
JAMB · Biology · 2018

A seed of a flowering plant can best be described as

A. radicle and plumule
B. the developed ovule
C. the embryo and endosperm
D. developed ovary
Explanation

A student might incorrectly select option A or C by focusing only on individual internal components like the radicle, plumule, or endosperm rather than the entire structure. Option B is correct because a seed is fundamentally formed as the developed ovule, which post-fertilization contains the embryo, endosperm, and protective seed coat. Common mistake: Confusing the final seed structure with the ovary, which develops into the fruit.

19
Question 19 of 40
JAMB · Biology · 2018

Which of the following processes removes carbon from the atmosphere?

A. Putrefaction
B. Photosynthesis
C. volcanic eruption
D. Burning fuels
Explanation

A student might mistakenly pick option D because burning fuels involves atmospheric processes, but combustion actually releases carbon rather than removing it. Option B is correct because green plants actively remove carbon dioxide from the surrounding air during the process of photosynthesis, converting it into stored glucose. Common mistake: Forgetting that combustion adds carbon to the atmosphere while photosynthesis takes it out.

20
Question 20 of 40
JAMB · Biology · 2018

Which of the following cycles involves the process of precipitation and transpiration?

A. Water cycles
B. Carbon cycle
C. Nitrogen cycle
D. oxygen cycle
Explanation

A student might select option B or C by misassociating precipitation with global elemental cycles, but neither the carbon nor nitrogen cycle specifically features rainfall. Option A is correct because the water cycle encompasses both precipitation, which returns water as rain, and transpiration, which releases water vapor from plants. Common mistake: Mixing up the specific biological and physical steps unique to the water cycle.

21
Question 21 of 40
JAMB · Biology · 2018

What is the critical limiting factor for plants below the photic zone in an aquatic ecosystem?

A. availability of nutrients
B. availability of water
C. intensity of light
D. carbon dioxide concentration
Explanation

A student might incorrectly choose option A or D, assuming nutrients or carbon dioxide limit deep-water life, since aquatic plants need various chemical resources. Option C is correct because plants located below the photic zone suffer from a severe lack of sunlight, making light intensity the critical limiting factor for their photosynthesis. Common mistake: Assuming nutrient limitation is always the primary constraint in deep aquatic environments.

22
Question 22 of 40
JAMB · Biology · 2018

Which of the following instruments is used to estimate the number of plants in a habitat?

A. Pooter
B. Pitfall trap
C. Quadrat
D. Sweep net
Explanation

A student might mistakenly choose a pooter or sweep net because those are also standard field equipment used for collecting small organisms. Option C is correct because a quadrat is specifically designed to estimate plant population sizes by counting individuals within a defined sample area. Common mistake: Confusing tools meant for capturing mobile insects with equipment used for stationary plant counts.

23
Question 23 of 40
JAMB · Biology · 2018

Which of the following statements is true about sandy soil? It

A. has limited air space
B. is light and easy to dig
C. retains a lot of water
D. is heavy and poorly aerated
Explanation

A student might incorrectly select option C or D, assuming that sandy soil holds moisture well or behaves like heavy clay. Option B is correct because sandy soil consists of large particles that create ample air space, rendering the ground light, well-aerated, and easy to dig. Common mistake: Believing that sandy soils are heavy and retain large amounts of water.

24
Question 24 of 40
JAMB · Biology · 2018

Which of the following organisms is a primary consumer?

A. Dog
B. Sheep
C. Grass
D. Fungus
Explanation

A student might mistakenly choose option A or D because dogs and fungi are common components of food webs, though they occupy different trophic levels. Option B is correct because sheep function as herbivores that feed directly on plants, placing them squarely in the primary consumer category. Common mistake: Confusing consumers that eat plants with carnivores or decomposers.

25
Question 25 of 40
JAMB · Biology · 2018

Which of the following organisms is a secondary consumer?

A. grasshopper
B. hawk
C. grass
D. cow
Explanation

A student might incorrectly pick option A or D by confusing herbivores with carnivores or failing to trace the trophic sequence properly. Option B is correct because a hawk preys directly on herbivores like grasshoppers, making it a secondary consumer in the trophic chain. Common mistake: Misidentifying primary consumers as secondary consumers.

26
Question 26 of 40
JAMB · Biology · 2018

Which of the following diseases is not hereditary?

A. Albinism
B. Scabies
C. Haemophilia
D. Colour blindness
Explanation

A student might mistakenly choose option A, C, or D because they are well-known inherited genetic conditions. Option B is correct because scabies is a contagious skin disease caused by parasitic mites rather than being passed down through genes. Common mistake: Assuming all medical conditions and skin ailments are hereditary.

27
Question 27 of 40
JAMB · Biology · 2018

The immediate product of meiosis in flowering plants is the

A. sporophytes
B. gametophyte
C. zygote
D. pollen grains
Explanation

A student might incorrectly select option C or D, confusing the immediate product of meiosis with mature pollen or a zygote. Option B is correct because meiosis in flowering plants directly yields gametophytes, which subsequently go on to form pollen grains or ovules. Common mistake: Forgetting that pollen grains develop from the immediate meiotic product known as the gametophyte.

28
Question 28 of 40
JAMB · Biology · 2018

DNA in eukaryotic cells is contained in the

A. central vacuole
B. nucleus
C. lysosome
D. golgi body
Explanation

A student might mistakenly choose option A, C, or D, thinking of other specialized organelles within a cell's cytoplasm. Option B is correct because eukaryotic cells securely store their DNA inside the nucleus, which is safely enclosed by the nuclear membrane. Common mistake: Assuming genetic material floats freely in organelles like vacuoles or lysosomes.

29
Question 29 of 40
JAMB · Biology · 2018

A man who is heterozygous for the disease haemophilia marries a woman who is double recessive for haemophilia. What percentage of their offspring would have the disease?

A. 0%
B. 25%
C. 50%
D. 75%
Explanation

A student might incorrectly guess 25% or 75% by misinterpreting standard monohybrid cross ratios or failing to draw the Punnett square correctly. Option C is correct because crossing a heterozygous man (XhY) with a double recessive woman (XhXh) results in 50% of their offspring inheriting the haemophilia condition across the possible XhY male and XhXh female combinations. Common mistake: Incorrectly reading sex-linked inheritance percentages.

30
Question 30 of 40
JAMB · Biology · 2018

Cytokinesis of mitosis is a process that ensures that

A. each daughter cell gets the necessary organelles
B. organelles are evenly distributed
C. the nuclear membrane reforms
D. chromosomes are separated
Explanation

A student might mistakenly select option C or D, confusing cytoplasmic division with nuclear events like chromosome separation or membrane reformation. Option A is correct because cytokinesis successfully divides the cytoplasm, ensuring that each newly formed daughter cell gets the necessary organelles to survive. Common mistake: Confusing nuclear division processes with the actual splitting of the cytoplasm and organelles.

31
Question 31 of 40
JAMB · Biology · 2018

An animal which is active during the day is known as a

A. nocturnal animal
B. diurnal animal
C. terrestrial animal
D. homoeothermic animal
Explanation

A student might incorrectly pick option A or D, confusing daytime activity with nighttime behaviors or temperature regulation terms. Option B is correct because a diurnal animal is specifically defined as being active during daylight hours, contrasting with nocturnal species. Common mistake: Mixing up the terms for day-active and night-active organisms.

32
Question 32 of 40
JAMB · Biology · 2018

A boy who is fond of swimming in a pond finds himself passing urine with traces of blood. He is likely to have contracted

A. schistosomiasis
B. onchocerciasis
C. poliomyelitis
D. salmonellosis
Explanation

A student might mistakenly choose option C or D, associating swimming ponds with general bacterial infections or paralysis rather than specific water-borne parasites. Option A is correct because schistosomiasis is contracted by swimming in freshwater containing parasitic worms, leading to blood in the urine. Common mistake: Confusing water-borne parasitic infections with food poisoning or viral diseases.

33
Question 33 of 40
JAMB · Biology · 2018

The flippers of a whale and the fins of a fish are examples of

A. divergent evolution
B. coevolution
C. continuous variation
D. convergent evolution
Explanation

A student might incorrectly select option A, C, or D by misidentifying the evolutionary mechanism behind analogous body parts in unrelated species. Option D is correct because the flippers of a whale and the fins of a fish are analogous structures that demonstrate convergent evolution for swimming in unrelated lineages. Common mistake: Confusing homologous and convergent evolutionary structures.

34
Question 34 of 40
JAMB · Biology · 2018

Which of the following is a characteristic of oviparous animals?

A. they give birth to live young
B. they lay eggs
C. they have internal fertilisation
D. they nurture their young in a pouch
Explanation

A student might mistakenly choose option A or C, confusing egg-laying species with mammals that give birth to live young. Option B is correct because oviparous animals, such as birds, lay eggs that complete their development outside the mother’s body. Common mistake: Confusing egg-bearing reproductive strategies with live-bearing viviparity.

35
Question 35 of 40
JAMB · Biology · 2018

Which of the following is a characteristic of viviparous animals?

A. they lay eggs
B. they give birth to live young
C. they have external fertilisation
D. they lack a placenta
Explanation

A student might mistakenly pick option A or C, attributing egg-laying or external fertilization traits to mammals. Option B is correct because viviparous animals, such as mammals, give birth to live young that have developed internally inside the mother. Common mistake: Mixing up viviparous live-bearing traits with oviparous egg-laying traits.

36
Question 36 of 40
JAMB · Biology · 2018

An accurate identification of a rapist can be carried out by conducting a

A. RNA analysis
B. DNA analysis
C. blood group test
D. behavioural traits test
Explanation

A student might incorrectly select option A or C, thinking that general blood typing or RNA checks are sufficient for positive suspect identification. Option B is correct because DNA analysis provides an accurate identification by precisely matching genetic material recovered from a crime scene. Common mistake: Relying on broad blood group tests instead of definitive DNA profiling.

37
Question 37 of 40
JAMB · Biology · 2018

What physiological term can be used to describe the regulation of the body temperature of a lizard?

A. Homeostasis
B. Homoithermy
C. Poikilothermy
D. Osmoregulation
Explanation

A student might mistakenly choose option A, B, or D, confusing body temperature control with internal chemical balance or constant thermal regulation. Option C is correct because lizards are poikilothermic, meaning their body temperatures fluctuate in direct response to the external environment. Common mistake: Confusing cold-blooded poikilothermy with warm-blooded homeostatic regulation.

38
Question 38 of 40
JAMB · Biology · 2018

Evidence of evolution include the following except

A. fossil records
B. comparative anatomy
C. mutation of genes
D. geographical distribution of organisms
Explanation

A student might incorrectly select option A, B, or D, thinking physical fossils or geographic ranges are not valid historical clues. Option C is correct because mutation of genes represents an ongoing cellular mechanism rather than serving as direct physical evidence of past evolution like fossil records or comparative anatomy. Common mistake: Confusing evolutionary mechanisms with direct historical evidence.

39
Question 39 of 40
JAMB · Biology · 2018

Which of the following is an example of a homologous structure?

A. wings of a bird and wings of an insect
B. flippers of a whale and fins of a fish
C. forelimbs of a human and wings of a bat
D. legs of a spider and legs of a crab
Explanation

A student might mistakenly pick option A or B by grouping any similarly shaped wings or swimming appendages together regardless of ancestry. Option C is correct because the forelimbs of a human and the wings of a bat are homologous structures sharing a common evolutionary origin despite different current uses. Common mistake: Failing to distinguish between analogous and homologous anatomical structures.

40
Question 40 of 40
JAMB · Biology · 2018

Which of the following is a method of preserving food in living organisms?

A. salting
B. boiling
C. freezing
D. all of the above
Explanation

A student might incorrectly choose a single method like salting or freezing, missing that multiple techniques apply. Option D is correct because salting, boiling, and freezing all effectively preserve food by inhibiting microbial growth through different mechanisms. Common mistake: Assuming only one single method exists for preserving biological food items.

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