JAMB Past Questions

JAMB Mathematics 2004
Questions & Answers

20 questions · Correct answers highlighted · 20 with explanations

Explanations reviewed August 2026

This 2004 JAMB Mathematics past paper covers a wide range of fundamental mathematical concepts tested across secondary school curricula. The questions consistently feature core topics such as quadratic equations, basic trigonometry, coordinate geometry, and descriptive statistics including mean, median, and probability. Use this page to test your problem-solving speed, and be sure to read the step-by-step solutions for any concepts you find challenging.

20 Total Questions
2004 Exam Year
20 With Explanations

Topics in this paper

Algebraic Expressions and Factorization (6) Statistics and Central Tendency (5) Trigonometric Ratios and Identities (4) Calculus and Derivatives (4) Logarithms and Indices (4) Mensuration and Areas (4) Ratios Proportions and Percentages (3) Coordinate Geometry (3) Probability and Combinatorics (2) Arithmetic Progressions (2) Surds and Radicals (1) Simultaneous Equations (1) Sets and Logic (1)
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1
Question 1 of 20
JAMB · Mathematics · 2004

Simplify (2/5 - 1/10) × 3.

A. 3/10
B. 9/10
C. 3/5
D. 6/5
Explanation

An incorrect subtraction of fractions by directly subtracting numerators and denominators without finding a common denominator leads many to wrong choices like 3/10 or 6/5. First, convert 2/5 into 4/10 so it can be subtracted by 1/10 to give 3/10, and then multiply that result by 3 to arrive at 9/10. Common mistake: Failing to find a common denominator before subtracting fractional quantities.

2
Question 2 of 20
JAMB · Mathematics · 2004

Solve the equation x² + 2x - 8 = 0.

A. x = 2, -4
B. x = -2, 4
C. x = 1, -8
D. x = -1, 8
Explanation

A careless sign error when factoring can easily cause a student to select options with positive values instead of negative roots. By factoring the quadratic expression into (x + 4)(x - 2) = 0, setting each factor to zero reveals the exact solutions are x = -4 and x = 2. Common mistake: Dropping or reversing negative signs during the factorization of quadratic roots.

3
Question 3 of 20
JAMB · Mathematics · 2004

Find the value of cos 45° × sin 45°.

A. 1/2
B. 1/√2
C. √2/2
D. 1/4
Explanation

Students might mistakenly pick √2/2 by forgetting that multiplying two identical radical fractions squares both the numerator and denominator. Since both cos 45° and sin 45° equal √2/2, multiplying them together gives (√2/2) × (√2/2) = 2/4, which simplifies to 1/2. Common mistake: Multiplying fractions with square roots by only multiplying the numerators and leaving the denominators unchanged.

4
Question 4 of 20
JAMB · Mathematics · 2004

The mean of seven numbers is 12. If one number is removed, the mean becomes 11. What is the removed number?

A. 16
B. 17
C. 18
D. 19
Explanation

A student might hastily subtract the two given mean values directly to find the difference, arriving at an incorrect number. Multiplying the original seven numbers by their mean of 12 gives a total sum of 84, while the remaining six numbers multiplied by their new mean of 11 yields 66, leaving 18 as the removed value upon subtraction. Common mistake: Subtracting averages directly instead of finding the difference between total sums.

5
Question 5 of 20
JAMB · Mathematics · 2004

What is the probability of drawing a king from a standard deck of 52 cards?

A. 1/13
B. 1/52
C. 1/4
D. 4/13
Explanation

Choosing 1/52 is a common error made by students who confuse the probability of drawing one specific card with drawing any card from the entire suit. Since a standard deck contains 4 kings out of 52 total cards, the correct probability fraction reduces from 4/52 to 1/13. Common mistake: Forgetting to account for the total number of matching target items in a collection when calculating probabilities.

6
Question 6 of 20
JAMB · Mathematics · 2004

Find the gradient of the line y = -3x + 5.

A. 3
B. -3
C. 5
D. -5
Explanation

Students might mistakenly select 5 by looking at the y-intercept constant instead of examining the coefficient attached to the variable x. In the slope-intercept form equation y = -3x + 5, the gradient m is explicitly represented by the coefficient of x, which is -3. Common mistake: Confusing the y-intercept value with the slope coefficient in linear equations.

7
Question 7 of 20
JAMB · Mathematics · 2004

Evaluate ∫(3x + 2) dx from x = 0 to x = 2.

A. 7
B. 8
C. 9
D. 10
Explanation

Evaluating an integral incorrectly by forgetting to raise the power of x can lead students to mismatched answers like 7 or 8. Integrating the expression (3x + 2) yields (3/2)x² + 2x, and substituting the upper limit of 2 gives (6 + 4) - 0 = 10. Common mistake: Incorrectly applying power rules during definite integration calculations.

8
Question 8 of 20
JAMB · Mathematics · 2004

If log₃(x) = 2, find x.

A. 6
B. 9
C. 12
D. 15
Explanation

Multiplying the base and exponent together to get 6 is a frequent error made by learners who confuse logarithms with basic multiplication. The logarithmic statement log₃(x) = 2 translates into exponential form as x = 3², which evaluates directly to 9. Common mistake: Treating logarithmic equations as linear multiplication problems instead of exponential inverses.

9
Question 9 of 20
JAMB · Mathematics · 2004

The nth term of a sequence is 4n + 1. What is the 6th term?

A. 23
B. 24
C. 25
D. 26
Explanation

An incorrect addition or failure to multiply properly can lead students to select alternative sequence values like 24. Substituting n = 6 into the given nth term formula 4n + 1 means multiplying 4 by 6 to get 24, and then adding 1 results in 25. Common mistake: Performing addition before multiplication when evaluating sequence formulas.

10
Question 10 of 20
JAMB · Mathematics · 2004

Find the area of a rectangle with length 10 cm and width 5 cm.

A. 40 cm²
B. 50 cm²
C. 60 cm²
D. 70 cm²
Explanation

Options like 40 cm² might be picked by mistakenly subtracting or using incorrect arithmetic. To find the correct area, multiply the given dimensions together, yielding 10 multiplied by 5, which results in 50 cm². Common mistake: Multiplying or adding dimensions incorrectly instead of taking length times width.

11
Question 11 of 20
JAMB · Mathematics · 2004

Simplify √(72) / √(8).

A. 3
B. √9
C. 6
D. √6
Explanation

A student might incorrectly choose √9 or √6 by mishandling the radical division. Combining the radicals under a single division yields 72 divided by 8, which simplifies to √9, and evaluating this gives 3. Common mistake: Stopping at the intermediate square root step instead of fully evaluating it.

12
Question 12 of 20
JAMB · Mathematics · 2004

Solve the system: 2x + y = 7 and x - 2y = 1.

A. x = 3, y = 1
B. x = 2, y = 3
C. x = 4, y = -1
D. x = 1, y = 5
Explanation

Options like x = 2, y = 3 look plausible if substitution errors are made. Expressing x in terms of y from the second equation as x equals 2y plus 1 allows substitution into the first expression to produce 2 times the quantity 2y plus 1 plus y equaling 7, which simplifies to 5y plus 2 equaling 7, ultimately determining y is 1 and x is 3. Common mistake: Distributing incorrectly when substituting the rearranged expression.

13
Question 13 of 20
JAMB · Mathematics · 2004

Find the value of sin 60°.

A. 1/2
B. √2/2
C. √3/2
D. 1
Explanation

Options such as 1/2 or √2/2 are easy to confuse with other standard angle ratios. Evaluating the trigonometric ratio for this specific angle relies on standard triangle values, directly giving √3/2 for the sine of 60 degrees. Common mistake: Mixing up the sine and cosine values for 30 and 60 degree angles.

14
Question 14 of 20
JAMB · Mathematics · 2004

Find the standard deviation of the numbers 1, 3, 5, 7, 9.

A. 2
B. 2.83
C. 3
D. 3.16
Explanation

A distractor like 2 or 3 might be guessed if variance is miscalculated. Computing the mean gives 5, and squaring the deviations from this mean produces 16, 4, 0, 4, and 16, which sum to 40; dividing by 5 yields a variance of 8, and taking the square root gives approximately 2.83. Common mistake: Forgetting to take the square root of the variance to find the standard deviation.

15
Question 15 of 20
JAMB · Mathematics · 2004

A circle has a diameter of 10 cm. What is its circumference?

A. 5π cm
B. 10π cm
C. 20π cm
D. 25π cm
Explanation

A student might mistakenly select 5π cm by confusing the radius with the diameter. Multiplying the given diameter of 10 cm by pi yields a circumference of 10π cm. Common mistake: Using the radius instead of the diameter when calculating the circumference.

16
Question 16 of 20
JAMB · Mathematics · 2004

Solve the inequality 3x + 2 > 11.

A. x > 3
B. x < 3
C. x > 4
D. x < 4
Explanation

Distractors like x < 3 arise from reversing the inequality sign during transposition. Subtracting 2 from both sides leaves 3x greater than 9, and dividing by 3 results in x being greater than 3. Common mistake: Flipping the inequality sign when dividing by a positive number.

17
Question 17 of 20
JAMB · Mathematics · 2004

Find the derivative of y = x⁴ + 3x².

A. 4x³ + 6x
B. 4x³ + 3x
C. x³ + 6x
D. 4x³ + 6
Explanation

Options such as 4x³ + 3x can tempt students who forget to apply the power rule correctly to every term. Differentiating x to the fourth power gives 4x³, and differentiating 3x squared gives 6x, combining to form 4x³ + 6x. Common mistake: Forgetting to multiply by the original exponent when applying the power rule.

18
Question 18 of 20
JAMB · Mathematics · 2004

If A = {2, 4, 6} and B = {4, 5, 6}, find A ∩ B.

A. {2, 5}
B. {4, 6}
C. {2, 4, 5, 6}
D. {}
Explanation

A student might mistakenly choose the union {2, 4, 5, 6} instead of the intersection. Finding the elements that appear in both sets identifies the common values 4 and 6, resulting in {4, 6}. Common mistake: Confusing set intersection with set union.

19
Question 19 of 20
JAMB · Mathematics · 2004

Evaluate 3³ × 2².

A. 54
B. 108
C. 81
D. 36
Explanation

An option like 54 might be chosen if exponents are multiplied by the base rather than evaluated as powers. Calculating 3 cubed gives 27, and 2 squared gives 4, which multiplied together equal 108. Common mistake: Multiplying the base by the exponent instead of raising it to that power.

20
Question 20 of 20
JAMB · Mathematics · 2004

Find the mode of the numbers 1, 2, 2, 3, 3, 3, 4.

A. 1
B. 2
C. 3
D. 4
Explanation

Options like 2 might be selected by confusing the mode with the median or mean. Examining the frequency of each number shows that 3 appears most frequently, making it the mode. Common mistake: Selecting the middle number instead of the most frequently occurring one.

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